0=4.9t^2+23.2849t+5

Solution for 0=4.9t^2+23.2849t+5 equation:

0=4.9t^2+23.2849t+5

We move all terms to the left:

0-(4.9t^2+23.2849t+5)=0

We add all the numbers together, and all the variables

-(4.9t^2+23.2849t+5)=0

We get rid of parentheses

-4.9t^2-23.2849t-5=0

a = -4.9; b = -23.2849; c = -5;
Δ = b2-4ac
Δ = -23.28492-4·(-4.9)·(-5)
Δ = 444.18656801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23.2849)-\sqrt{444.18656801}}{2*-4.9}=\frac{23.2849-\sqrt{444.18656801}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23.2849)+\sqrt{444.18656801}}{2*-4.9}=\frac{23.2849+\sqrt{444.18656801}}{-9.8}
$